VALID ORACLE 1Z1-830 TEST BLUEPRINT, RELIABLE 1Z1-830 TEST SYLLABUS

Valid Oracle 1z1-830 Test Blueprint, Reliable 1z1-830 Test Syllabus

Valid Oracle 1z1-830 Test Blueprint, Reliable 1z1-830 Test Syllabus

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Oracle Java SE 21 Developer Professional Sample Questions (Q18-Q23):

NEW QUESTION # 18
Given:
java
public class SpecialAddition extends Addition implements Special {
public static void main(String[] args) {
System.out.println(new SpecialAddition().add());
}
int add() {
return --foo + bar--;
}
}
class Addition {
int foo = 1;
}
interface Special {
int bar = 1;
}
What is printed?

  • A. Compilation fails.
  • B. 0
  • C. 1
  • D. 2
  • E. It throws an exception at runtime.

Answer: A

Explanation:
1. Why does the compilation fail?
* The interface Special contains bar as int bar = 1;.
* In Java, all interface fields are implicitly public, static, and final.
* This means that bar is a constant (final variable).
* The method add() contains bar--, which attempts to modify bar.
* Since bar is final, it cannot be modified, causing acompilation error.
2. Correcting the Code
To make the code compile, bar must not be final. One way to fix this:
java
class SpecialImpl implements Special {
int bar = 1;
}
Or modify the add() method:
java
int add() {
return --foo + bar; // No modification of bar
}
Thus, the correct answer is:Compilation fails.
References:
* Java SE 21 - Interfaces
* Java SE 21 - Final Variables


NEW QUESTION # 19
Given:
java
String colors = "redn" +
"greenn" +
"bluen";
Which text block can replace the above code?

  • A. None of the propositions
  • B. java
    String colors = """
    red
    green
    blue
    """;
  • C. java
    String colors = """
    red
    green
    blue
    """;
  • D. java
    String colors = """
    red s
    greens
    blue s
    """;
  • E. java
    String colors = """
    red t
    greent
    blue t
    """;

Answer: C

Explanation:
* Understanding Multi-line Strings in Java (""" Text Blocks)
* Java 13 introducedtext blocks ("""), allowing multi-line stringswithout needing explicit n for new lines.
* In a text block,each line is preserved as it appears in the source code.
* Analyzing the Options
* Option A: (Backslash Continuation)
* The backslash () at the end of a lineprevents a new line from being added, meaning:
nginx
red green blue
* Incorrect.
* Option B: s (Whitespace Escape)
* s represents asingle space,not a new line.
* The output would be:
nginx
red green blue
* Incorrect.
* Option C: t (Tab Escape)
* t inserts atab, not a new line.
* The output would be:
nginx
red green blue
* Incorrect.
* Option D: Correct Text Block
java
String colors = """
red
green
blue
""";
* Thispreserves the new lines, producing:
nginx
red
green
blue
* Correct.
Thus, the correct answer is:"String colors = """ red green blue """."
References:
* Java SE 21 - Text Blocks
* Java SE 21 - String Formatting


NEW QUESTION # 20
A module com.eiffeltower.shop with the related sources in the src directory.
That module requires com.eiffeltower.membership, available in a JAR located in the lib directory.
What is the command to compile the module com.eiffeltower.shop?

  • A. css
    CopyEdit
    javac --module-source-path src -p lib/com.eiffel.membership.jar -s out -m com.eiffeltower.shop
  • B. css
    CopyEdit
    javac --module-source-path src -p lib/com.eiffel.membership.jar -d out -m com.eiffeltower.shop
  • C. bash
    CopyEdit
    javac -source src -p lib/com.eiffel.membership.jar -d out -m com.eiffeltower.shop
  • D. css
    CopyEdit
    javac -path src -p lib/com.eiffel.membership.jar -d out -m com.eiffeltower.shop

Answer: B

Explanation:
Comprehensive and Detailed In-Depth Explanation:
Understanding Java Module Compilation (javac)
Java modules are compiled using the javac command with specific options to specify:
* Where the source files are located (--module-source-path)
* Where required dependencies (external modules) are located (-p / --module-path)
* Where the compiled output should be placed (-d)
Breaking Down the Correct Compilation Command
css
CopyEdit
javac --module-source-path src -p lib/com.eiffel.membership.jar -d out -m com.eiffeltower.shop
* --module-source-path src # Specifies the directory where module sources are located.
* -p lib/com.eiffel.membership.jar # Specifies the module path (JAR dependency in lib).
* -d out # Specifies the output directory for compiled .class files.
* -m com.eiffeltower.shop # Specifies the module to compile (com.eiffeltower.shop).


NEW QUESTION # 21
Given:
java
public class Test {
class A {
}
static class B {
}
public static void main(String[] args) {
// Insert here
}
}
Which three of the following are valid statements when inserted into the given program?

  • A. A a = new Test.A();
  • B. B b = new Test.B();
  • C. A a = new A();
  • D. A a = new Test().new A();
  • E. B b = new Test().new B();
  • F. B b = new B();

Answer: B,D,F

Explanation:
In the provided code, we have two inner classes within the Test class:
* Class A:
* An inner (non-static) class.
* Instances of A are associated with an instance of the enclosing Test class.
* Class B:
* A static nested class.
* Instances of B are not associated with any instance of the enclosing Test class and can be instantiated without an instance of Test.
Evaluation of Statements:
A: A a = new A();
* Invalid.Since A is a non-static inner class, it requires an instance of the enclosing class Test to be instantiated. Attempting to instantiate A without an instance of Test will result in a compilation error.
B: B b = new Test.B();
* Valid.B is a static nested class and can be instantiated without an instance of Test. This syntax is correct.
C: A a = new Test.A();
* Invalid.Even though A is referenced through Test, it is a non-static inner class and requires an instance of Test for instantiation. This will result in a compilation error.
D: B b = new Test().new B();
* Invalid.While this syntax is used for instantiating non-static inner classes, B is a static nested class and does not require an instance of Test. This will result in a compilation error.
E: B b = new B();
* Valid.Since B is a static nested class, it can be instantiated directly without referencing the enclosing class.
F: A a = new Test().new A();
* Valid.This is the correct syntax for instantiating a non-static inner class. An instance of Test is created, and then an instance of A is created associated with that Test instance.
Therefore, the valid statements are B, E, and F.


NEW QUESTION # 22
Given:
java
String s = " ";
System.out.print("[" + s.strip());
s = " hello ";
System.out.print("," + s.strip());
s = "h i ";
System.out.print("," + s.strip() + "]");
What is printed?

  • A. [ ,hello,h i]
  • B. [,hello,hi]
  • C. [ , hello ,hi ]
  • D. [,hello,h i]

Answer: D

Explanation:
In this code, the strip() method is used to remove leading and trailing whitespace from strings. The strip() method, introduced in Java 11, is Unicode-aware and removes all leading and trailing characters that are considered whitespace according to the Unicode standard.
docs.oracle.com
Analysis of Each Statement:
* First Statement:
java
String s = " ";
System.out.print("[" + s.strip());
* The string s contains four spaces.
* Applying s.strip() removes all leading and trailing spaces, resulting in an empty string.
* The output is "[" followed by the empty string, so the printed result is "[".
* Second Statement:
java
s = " hello ";
System.out.print("," + s.strip());
* The string s is now " hello ".
* Applying s.strip() removes all leading and trailing spaces, resulting in "hello".
* The output is "," followed by "hello", so the printed result is ",hello".
* Third Statement:
java
s = "h i ";
System.out.print("," + s.strip() + "]");
* The string s is now "h i ".
* Applying s.strip() removes the trailing spaces, resulting in "h i".
* The output is "," followed by "h i" and then "]", so the printed result is ",h i]".
Combined Output:
Combining all parts, the final output is:
css
[,hello,h i]


NEW QUESTION # 23
......

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